divide Rs 1216 into three parts such that the first part is 1/5 of second part and ratio of second part to third is 3:4.
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according to the question 3x rupees are given to 2nd and 4x are rupees are given to 3rd(because ratio is 3:4) and 3x/5 are given to the 1st
therefore equation is
3x/5 + 3x + 4x = 1216
( 3x+15x+20x)/5 = 1216
38x/5 = 1216
x=(1216*5)/38= 6080/38 = 160
therefore rupees are given to 1st =( 3*160)/5
=480/5= 96 rupees
rupees are given to 2nd = 3*160= 480 rupees
rupees are given to 3rd = 4*160= 640 rupees
therefore equation is
3x/5 + 3x + 4x = 1216
( 3x+15x+20x)/5 = 1216
38x/5 = 1216
x=(1216*5)/38= 6080/38 = 160
therefore rupees are given to 1st =( 3*160)/5
=480/5= 96 rupees
rupees are given to 2nd = 3*160= 480 rupees
rupees are given to 3rd = 4*160= 640 rupees
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