divide Rs 1250 among a,b,c respectively, so that a gets 2/9 of b's share and c geta 3/4 of a's share
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let b gets Rs x
according to the problem;
a's share = (2/9)*x
c's share = (3/4)*(a's share) = (3/4)*(2/9)*x = (6/36)*x = (1/6)*x
so, all the shares should sum upto the original amount
ie, [(2/9)*x] + [x] + [(1/6)*x] = 1250
now solve for x from the above expression
value of x will come 900
so, a's share = (2/9)*x = (2/9)*900 = Rs. 200
b's share = x = Rs. 900
c's share = (1/6)*x = (1/6)*900 =Rs. 150
according to the problem;
a's share = (2/9)*x
c's share = (3/4)*(a's share) = (3/4)*(2/9)*x = (6/36)*x = (1/6)*x
so, all the shares should sum upto the original amount
ie, [(2/9)*x] + [x] + [(1/6)*x] = 1250
now solve for x from the above expression
value of x will come 900
so, a's share = (2/9)*x = (2/9)*900 = Rs. 200
b's share = x = Rs. 900
c's share = (1/6)*x = (1/6)*900 =Rs. 150
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