Question

divide Rs.1290 into A,B,C such that A is 2/5 of B and B :C=4:3

Answer 1

by the question A+B+C=1290.... equation (1)
given relation
A=2/5 B
B=5/2 A... equation (2)
B/C =4/3
C=3/4 B.... equation (3)
substituting equation (2) & (3) in (1)
2/5 B + B + 3/4 B = 1290
B (2/5 + 1 + 3/4)= 1290
B {(8+20+15)/20} = 1290
B {43/20} = 1290
B =1290 × 20/43
B =25800/43
B =600
Then,
A =2/5 B
A =2/5 ×600
A =2×120
A =240
Then,
C =3/4 B
C =3/4 × 600
C =3 × 150
C =450
Finally, A=240Rs , B=600Rs and C=450Rs