Math, asked by Popsicle1077, 1 year ago

Divide Rs 200 into two parts such that one third of the first and one half of the Second are equal

Answers

Answered by aneeshrout
14

Answer:


Step-by-step explanation:

Let the parts be X and Y

1/3X = 1/2Y.

2/3X=Y -i

X +Y =200. -ii

Substitution of Y in equation (ii)

(3X + 2X) /3 = 200

5X = 600

X = 120

In equation (i)

Y = 80

The two parts are 120 and 80

Answered by DebopamRoy
5
Let 1 part be x and the other be y
According to the problem,
x/3=y/2
or x=3y/2
Therefore ,
x+y=₹200
or 3y/2+y=₹200
or 5y/2=₹200
or 5y=₹200*2
or y=₹400/5
or y=₹80
Therefore x =3y/2=₹120
The two parts are ₹80 and ₹120
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