Question

Divide Rs 200 into two such parts such that 1/3 of the first and 1/2 of the second are equal.​ the large of the part is​

Answer 1

200=120,80

120×1/3=40

80×1/2=40

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Answer 2

Step-by-step explanation:

Given amount=Rs. 200

On dividing the amount into 1/3 the first and the 1/2 of the second

The ratio =1/2:1/3=3:2

Let they be 3x and 2x

Total parts =3x+2x=5x

=>5x=200

=>x=200/5

=>x=40

3x=3(40)=120

2x=2(40)=80

The two parts =120 and 80

The largest part =Rs.120