Question

Divide Rs.243 into three parts such that half of the first part, one-third of the second part and one-fourth of the third part shall be equal

Answer 1

let the parts be
1st=x
2nd=y
3rd=z
½x=⅓y=¼z
x+y+z=243
½x=⅓y so y=3/2x
⅓y=¼z so z=4/3y put value of y here
z=(4/3)(3/2x)
z=2x

x+y+z=243
x+3/2x+2x=243
(2x+3x+4x)/2=243
4.5x=243
x=243/4.5
x=54
y=3/2*54=81
z=2*54=108

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