Math, asked by santhuthara805, 1 year ago

Divide Rs 300 into two parts such that half of one part may be less than the other by 48. Find the parts?

Answers

Answered by Shreya142931
57
Let 300 be divided into x and 300
According to rhe question,
300-x-1/2x=48
300-48=x+x/2
252=3x/2
x=252×2/3
=168
300-x=300-168=132

Gyankashyap: I have also gotten
Answered by kjuli1766
3

Concept

Addition, Subtraction and Division are the three major arithmetic operations used in maths.

Given

1) Total = Rs. 300

2) 300 is divided in two parts

3) Half of one part may be less than the other by 48

Find

Find the parts

Solution

Let the first part be x

Other part is 300-x

We are given that Half of one part may be less than the other by 48

So,

x/2 = 300 – x - 48

x/2 + x = 252

3x/2 = 252

x = 252*2/3

x = 504/3

x = 168

300-x = 132

The parts are 168 and 132.

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