Divide Rs 300 into two parts such that half of one part may be less than the other by 48. Find the parts?
Answers
Answered by
57
Let 300 be divided into x and 300
According to rhe question,
300-x-1/2x=48
300-48=x+x/2
252=3x/2
x=252×2/3
=168
300-x=300-168=132
According to rhe question,
300-x-1/2x=48
300-48=x+x/2
252=3x/2
x=252×2/3
=168
300-x=300-168=132
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Answered by
3
Concept
Addition, Subtraction and Division are the three major arithmetic operations used in maths.
Given
1) Total = Rs. 300
2) 300 is divided in two parts
3) Half of one part may be less than the other by 48
Find
Find the parts
Solution
Let the first part be x
Other part is 300-x
We are given that Half of one part may be less than the other by 48
So,
x/2 = 300 – x - 48
x/2 + x = 252
3x/2 = 252
x = 252*2/3
x = 504/3
x = 168
300-x = 132
The parts are 168 and 132.
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