Question

divide rs 3600 into two parts such that if one part be lent at 9% per annum and the other at 10% per annum ,the total annual income is rs 333.​

Answer 1

Step-by-step explanation:

Given

Total income = Rs. 333

Let the first part which lent at the rate of 9% be x

And the other part which is lent at the rate of 10% be (3600 – x)

$\sf \: x \: \times \frac{9}{100 } + (3600 - x) \times \frac{10}{100} = 333 \\ \sf \: 0.09x \: + 3600 - 0.1x = 333 \\ \sf \: 0.01x = 27 \\ \sf \: x = 2700$

$\sf \: The \: money \: lent \: at \: 9\% \: is \: Rs. 2700$

$\sf \: the \: other \: which \: is \: 10\% is \: Rs. 900.$

Answer 2

Answer:

Let Rs.3600 be divided into two parts x and y respectively.

x+y=3600

y=3600−x

As we know that,

S.I.=

100

P×R×t

Now,

For Rs.x,

Rate of interest =9% per annum

t=1

S.I.=

100

x×9×1

For Rs.y,

Rate of interest =10% per annum

t=1

S.I.=

100

y×10×1

⇒S.I.=

100

(3600−x)×10

Now, according to the question-

100

9x

+

100

10(3600−x)

=333

⇒9x+36000−10x=33300

⇒x=36000−33300=2700

Therefore,

y=3600−2700=900

Hence Rs.3600 can be divided in Rs.2700 and Rs.900 respectively.

Step-by-step explanation:

hope it helps you siso ❤️