Math, asked by Anonymous, 11 months ago

Divide Rs.370 into three parts such that second part is 1/4of the third part and the ratio between the first and the third part is 3:5.Find each part

Answers

Answered by RJ59
3

Answer:

3 no are A,B,&C

A:C=3:5

&

B:C=1:4

IN A:C=3:5=12:20

&

IN B:C=1:4=5:20

Comparing A:C&B:C

A:B:C=12:5:20

COMMON FACTOR IS X

12X+5X+20X=370

37X=370

X=10

SO NUMBER ARE

A=12*10=120

B=5*10=50

C=20*10=200

Answered by sonabrainly
4

Answer:

Step-by-step explanation:

Let first and third parts be 3x and 5x (the ratio is 3:5)

Given that second part is (1/4) of third part

Therefore second part = 5x/4

Now

Sum of all three parts = ₹370

3x + (5x/4) + 5x = 370

(12x + 5x + 20x)/4 = 370

37x/4 = 370

Dividing whole equation by 37

x/4 = 10

x = 40

Therefore

First Part = 3x = ₹120

Third Part = 5x = ₹200

Second part = 5x/4 = ₹50

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