Question

Divide Rs 64 between A and B, so that three times A's share is greater than four times B's share by Rs 10.​

Answer 1

Solution-

Total share is given Rs 64

Let share of A be Rs x and of B be Rs y

Given : 3x = 4y + 10

x= (4y +10) /3 -eqn 1

64 = x+y

64= (4y +10) /3 + y (put value of x)

Solving above eqn we get,

y= Rs 26

Put the value of y in eqn 1 , we get

x= Rs 38

So the share of A is Rs 38 and

Share of B is Rs 26

Answer 2

Answer:

A's share is ₹38

B's share is ₹ 26

Step-by-step explanation:

Total money to be divided is ₹64

Let A's share be x

Therefore, B's share = (64-x)

A/Q

3x = 4×(64-x)+10

=> 3x = 256-4x+10

=> 3x+4x = 256+10

=> 7x = 266

=> x = 266/7

=> x = 38

Therefore,

A's share is ₹38

A's share is ₹38B's share = ₹(64-38)

= ₹ 26