Question

divide rs 91 among three brothers in a such way that the eldest gets twice as much the youngest and 3/2 times as much as the middle brother find the share eldest brother.​

Answer 1

Step-by-step explanation:

Let A be the eldest, B middle and C be the youngest brother. Now as the eldest gets twice as the youngest, we can say that if C gets 1, then A gets 2. And also the share of A is 3/2 of B, so in this case, let the share of B is n. Then 2= 3/2 n which in turn gives n= 4/3. So the share of B is 4/3. Then ratio becomes:

2: 4/3: 1.

Or simplifying by multiplying with 3,

6: 4: 3

Now 6+4+3=13

So share of A is 6/13 of 91 i.e. 42.

Answer 2

Answer:

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Step-by-step explanation:

Let A be the eldest, B middle and C be the youngest brother. Now as the eldest gets twice as the youngest, we can say that if C gets 1, then A gets 2. And also the share of A is 3/2 of B, so in this case, let the share of B is n. Then 2= 3/2 n which in turn gives n= 4/3. So the share of B is 4/3. Then ratio becomes:

2: 4/3: 1.

Or simplifying by multiplying with 3,

6: 4: 3

Now 6+4+3=13

So share of A is 6/13 of 91 i.e. 42.