Question

divide rthcube +1 by r+1

Answer 1

$\bold{\underline{Answer} :}$

We know that,

${x}^{3}+{y}^{3}=(x+y)({x}^{2}-xy+{y}^{2})$

Now, ${r}^{3}+1=(r+1)({r}^{2}-r+1)$

When we will divide $({r}^{3}+1)$ by (r + 1), (r + 1) will get cancelled from the terms of $({r}^{3}+1).$

Hence, the required solution be $\bold{({r}^{2}-r+1)}$

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