Question

divide rupee 1380 among A,B and C such that A gets 5 times of C's and 3 times of B's share

Answer 1

Let A=5C be equation 1.
Let A=3B be equation 2.
From 1 and 2 we get 5C=3B. Therefore B=(5/3)C. Let it be equation 3.
Also, A+B+C=1380.
Substituting equations 1 and 3 we get,
5C+(5/3)C+C=1380
Solving this we get, C=180.
Substituting in 3 we get, B=300.
Again substituting in 2 we get, A=900.