Math, asked by Ayanhusain, 1 year ago

divide rupee 25,000 between A, B and C so that a gets 7/8 of B and C gets 2/3 of A and B

Answers

Answered by sibhiamar
2
divide rupee 25,000 between A, B and C
so, A + B + C = 25000.............(1)

A gets 7/8 of B
so, A = 7B/8

C gets 2/3 of A and B
so, C = (2/3) × (A+B)
C = (2/3) × ((7B/8)+B)
C = (2/3) × ((7B+8B)/8)
C = (2/3) × (15B/8)
C = 5B/4

substitute A and C in (1)
(7B/8) + B + (5B/4) = 25000
(7B + 8B + 10B)/8 = 25000
25B/8 = 25000
B = 25000 × (8/25)
B = 8000

A = (7 × 8000)/8
A = 7000

C = (5 × 8000)/4
C = 10000

A gets 7000, B gets 8000, C gets 10000
Answered by jalppatel1515
0

Step-by-step explanation:

mark me as brainliest ok

Attachments:
Similar questions