Math, asked by kaurekamjot464, 5 hours ago

divide rupees 1400 into three parts such that the first part is 2 / 3 of the second part and the ratio between the second and third part is 4 : 5 find each part​

Answers

Answered by sonambansode8
0

Step-by-step explanation:

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Answered by itzinnocentbndii
5

Answer:

Answer: The three parts of the number 1400 where the 1st part is 2/3 of 2nd part and the ratio between the 2nd and 3rd part is 4:5 are 320, 480, and 600.

The general form of representing a ratio of two quantities say 'a' and 'b' is a : b

Step-by-step explanation:

Let's assume the 1st part 2nd part and the 3rd part as, 'x', 'y', and 'z'.

Since, the 1st part is 2/3 of 2nd part, therefore x = (2/3) y

Now, the ratio between the 2nd and 3rd part is 4:5, therefore y/z = 4/5

Now, use the equation y/z = 4/5 and calculate the value of 'z' in terms of 'y':

y/z = 4/5

=> 4z = 5y

=> z = (5/4)y

As the sum of all the three parts is equal to 1400,

=> x + y + z = 1400

=> (2/3) y + y + (5/4)y = 1400

=> ((8+12+15)/12)y = 1400

=> 35/12 y =1400

=> y= (1400 × 12)/35

=> y = 480

Now, substitute y = 480 in the equation x = (2/3) y to calculate the first number

x = (2/3) × 480

=> x = 320

Now substitute y = 480 in the equation z = (5/4)y to calculate the third number

z = (5/4) × 480

=> z = 600

Therefore, the three parts are 320, 480, and 600

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