Math, asked by satissunayu, 1 year ago

divide rupees 1430 among Suman Sheela and meeta in such a way that Sheela gets three times what Suman Gets and meeta gets half of what sheela gets

Answers

Answered by gaurav2013c
9
Let the money Suman get be a

Money Sheela get = 3a

Money Meeta get = 3a/2

Now,

Total money = 1430

a + 3a + 3a/2 = 1430

=> ( 2a + 6a + 3a) /2 = 1430

=> 11a = 2860

=> a = 260

Suman's share = Rs 260

Sheela's share = 260 × 3 = Rs 780

Meeta's share = 780 / 2 = Rs 390
Answered by clashrox63
1

Answer:

Step-by-step explanation:

Let Suman get ₹ x.

Thus Sheela gets ₹ 3x

and Meets gets ₹1.5x

Now

x + 3x + 1.5x = 1430 as we have to divide 1430 in the given share.

thus, 5.5x = 1430

Thus x= ₹260

Therefore

Suman gets ₹260,

Sheela gets ₹ 780,

Neeta gets ₹ 390

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