Question

divide rupees 2420 among A,B,C in the ratio of 4/3,3/2,5/6

Answer 1

$\bold {\huge {Solutions:-}}$

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Q: Divide rupees 2420 among A,B,C in the ratio of 4/3,3/2,5/6.  
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Let the ratio be A = 4/3x

B = 3/2x

C = 5/6x  

So, when we added A+B+C then we get 2420  

A/q

 4/3x + 3/2x + 5/6x = 2420

 => (8x + 9x + 5x) /6 = 2420

 => 22x = 2420×6  

=> x = 14520/22  

=> 660  

Now,  
A = 4/3x = 4/3×660 = ₹880


 B = 3/2x = 3/2×660 = ₹990

 C = 5/6x = 5/6×660 = ₹550

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{solution}}}$

$<b>$

$\huge\underline{\purple{\bold{Let\:ratio\:be\:X}}}$

A = 4/3x↩

B = 3/2x ↩

C = 5/6x  ↩

$\huge\underline{\purple{\bold{Now}}}$

when we added A+B+C then we get 2420 . 

According to question.

 4/3x + 3/2x + 5/6x = 2420 

 ➡(8x + 9x + 5x) /6 = 2420 

 ➡22x = 2420×6  

➡ x = 14520/22  

➡ 660   
$\huge\boxed{\purple{\bold{Answer}}}$

A➡4/3x=4/3×660=880rupees•

B➡3/2x=3/2×660=990rupees•

C➡5/6x=5/6×660= 550 rupees•