Question

divide rupees 2648 among A,B and C in such a way that B receives rupees 28 less than twice that of what A receives and C receives rupees 24 less than thrice that of what A receives​

Answer 1

➤ Answer

• Money with A = ₹450.
• Money with B = ₹872.
• Money with C = ₹1326.

➤ To Do

• To divide money among A,B and C in such that B receives rupees 28 less than twice that of what A receives and C receives rupees 24 less than thrice that of what A receives

➤ Given

• Total money = ₹ 2648

➤ Step By Step Explanation

➠ Assumption

Let us consider the money with A be x. Then the money with B will be 2x - 8 and money with C will be 3x - 24.

➠ Equation

$\dag\underline{\boxed{\sf{x + 2x - 28 + 3x - 24 = 2648}}}$

➠ Solution of Equation

$\longmapsto\tt x + 2x - 28 + 3x - 24 = 2648 \\ \\\longmapsto\tt 6x - 52 = 2648 \\ \\\longmapsto\tt 6x = 2648 + 52 \\ \\\longmapsto\tt 6x = 2700 \\ \\\longmapsto\tt x = \cancel\cfrac{2700}{6} \\ \\\longmapsto\tt x = 450$

➵ Therefore,

Money with A = ₹450.

Money with B = 2 × 450 - 8 => 900 - 28 => ₹872.

Money with C = 3 × 450 - 24 => 1350 - 24 => ₹1326.

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Answer 2

Step-by-step explanation:

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