divide rupees 90 into two parts so that the ratio between their difference and sum 1 ratio 9
Answers
Answered by
8
Answer. 40 and 50.
Solution
Let x be the smaller of the two parts.
Then the other part is 90-x.
Notice that the sum of these parts is precisely 90, while the difference is (90-x) - x = 90-2x.
Then, according to the condition,
= , ----->
= ,
90 - 2x = 10,
2x = 90 - 10 = 80,
x = = 40.
Thus the smallest part is 40, and the other part is 90-40 = 50.
Solution
Let x be the smaller of the two parts.
Then the other part is 90-x.
Notice that the sum of these parts is precisely 90, while the difference is (90-x) - x = 90-2x.
Then, according to the condition,
= , ----->
= ,
90 - 2x = 10,
2x = 90 - 10 = 80,
x = = 40.
Thus the smallest part is 40, and the other part is 90-40 = 50.
Answered by
3
Answer:
40 and 50
Step-by-step explanation:
Let 2 parts be x and 90-x
x-90-x:x+90-x::1:9
2x-90/90=1/9
2x-90=10
2x=100
x=50
One number is 50
Other number is 90-50=40
Therefore, two numbers are 40 and 50
PLEASE MARK BRAINIEST
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