Question

Divide segment AB of length 7 cm into a ratio 3:2?​

Answer 1

Answer:

Step-by-step explanation:

Step-by-step explanation:

Śtep 1 - draw Ray AC making an acute angel with AB.

Step 2- starting with A, mark of 5 points

C1, C2, C3, C4, C5 at equal distance from the point A.

Step 3- Join C5 and B.

Step 4- Through C2 (I. e the second point), draw C2 and D parallel to C5 B meeting AB in D.

Then D is required points, which divides AB segment into 2:3 part

Answer 2

Step-by-step explanation:

Given: AB is a line segment of 7 cm length. Required: To divide a line segment of 7 cm length externally in the ratio of 3 : 5.

Steps of Construction:1. Draw the line segment AB = 7 cm.

2. Draw ray BX making an acute ∠ ABX .3. Along BX, mark off five points B1, , B2, B3, , B4 and B5. Join B2 to A.

4. Through B5 draw B5P || B2A , intersecting BA produced at P.

5. The point P so obtained is the required point which divides AB externally in the ratio3 : 5.Proof: In Δs ABB2 and PBB5, B5P || B2A ⇒ ABB2 ∼ PBB5∴

=

(Property of similarty).⇒