Question

Divide:
$13 \sqrt{3 {t}^{3} } by \sqrt{39 {t}^{2} }$
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Answer 1

Answer:

lol

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$13 \sqrt{3 {t}^{3} } \div \sqrt{39 {t}^{2} } \\ \\ = \frac{13 \sqrt{3 {t}^{3} } }{ \sqrt{39} \: t} \\ \\ = \frac{ \sqrt{13} \times \sqrt{13} \times \sqrt{3 {t}^{3} } }{ \sqrt{13} \times \sqrt{3} \times t} \\ \\ = \frac{ \sqrt{13} \times \sqrt{ {t}^{2} } \times \sqrt{t} }{t} \\ \\ = \sqrt{13t}$