Question

divide
$40x^{2} + 11x - 63$
by
$8x - 9$
please answer my question with steps ​

Answer 1

$(40x^{2} + 11x - 63 ) \div (8x-9)$

$=\frac{ (40x^{2} + 11x - 63 )}{(8x-9)} \\= \frac{ 40x^{2} +56x - 45x - 63 }{(8x-9) } \\= \frac{ 8x(5x + 7 )- 9( 5x+7) }{(8x-9) } \\= \frac{(5x+7)(8x-9)}{(8x-9)}\\= 5x+7$

Therefore.,

$\red{(40x^{2} + 11x - 63 ) \div (8x-9)}\green{=5x+7 }$

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Answer 2

Step-by-step explanation:

Hope it helps you and please make my answer as brainlist answer