Question

Divide
$\sqrt[3]{128} \: by \: \sqrt[5]{64}$

Answer 1

Hi friend, Harish here.

Here is your answer:

We know that,

128 = 2⁷  &   64 = 2⁶

Then,

$\sqrt[3]{128} \div \sqrt[5]{64} = 2^{( \frac{7}{3} )} \div 2^{(\frac{6}{5})}$

⇒ $2^{( \frac{7}{3} )} \times 2^{(\frac{-6}{5})} = 2^{( \frac{7}{3} )+( \frac{-6}{5} )}$

⇒  $2^{( \frac{17}{15} )}$
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Hope my answer is helpful to you.