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please solve my problem
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Answer:
Given expression is x4y4−xy
We can take out xy as common.
Hence, the expression becomes:
xy(x3y3−1)
⇒xy[(xy)3−13]
We know that, a3−b3=(a−b)(a2+b2+ab)
Hence, the expression becomes:
xy[(xy−1)((xy)2+12+1(xy))]
⇒xy[(xy−1)(x2y2+1+xy)]
⇒xy(xy−1)(x2y2+xy+1)
Hence, x4y4−xy=xy(xy−1)(x2y2+xy+1).
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