Question

Divide the 3740 into three parts in such a way that the first half, one third of the second and the sixth part of the third are equal in each other:

Answer 1

Answer:

680, 1020, 2040

Step-by-step explanation:

let the three numbers be x, y and z

x + y + z = 3740

$\frac{x}{2} = \frac{y}{3} = \frac{z}{6} \\ \\ \frac{x}{2} = \frac{y}{3} \\ y = \frac{3x}{2} \\ \\ \frac{x}{2} = \frac{z}{6} \\ z = \frac{6x}{2} = 3x \\ \\ x + \frac{3x}{2} + 3x = 3740 \\ \frac{2x + 3x + 6x}{2} = 3740 \\ 2x + 3x + 6x = 3740 \times 2 \\ 11x = 7480 \\ x = \frac{7480}{11} = 680$

the numbers are

x = 680

y = 3x/2 = 3 × 680/2 = 3 × 340 = 1020

z = 3x = 3 × 680 = 2040

x + y + z

= 680 + 1020 + 2040

= 3740

hope you get your answer