Divide the algebraic expressions by using factorization method:
(i) 25pq(25p^2 - 4q^2) ÷5p(5p-2q)
(ii) 42n^2(32-98n^2) ÷98n^2(7n+4)
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Answer:
I)
25pq(25p^2-4q^2)÷5p(5p-2q)
=5q{(5p)^2-(2q)^2}÷(5p-2q)
=5q(5p+2q)(5p-2q)÷(5p-2q)
=5q(5p+2q)
ii) 42n^2(32-98n^2)÷98n^2(7n+4)
=42 n^2.2(16-49n^2)÷98n^2(7n+4)
=84{(4)^2-(7n)^2}÷98(7n+4)
=6(4+7n)(4-7n)÷7(4+7n)
=6(4-7n)/7
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