Question

divide the first algebraic expression by this second algebraic expression - 9xy cube, xy

please solve it quickly and I'll mark as u a brainliest ✨​

Answer 1

Answer:

${ - 9xy}^{3} \div xy = \frac{- 9xy \times y \times y}{xy} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {- 9 \times {y}^{2}} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 9 {y}^{2} \: \: \: \: \: \: (xy \: is \: cancelled \: in \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: numerator \: and \: denominator)$

Hope it helps u pls mark as brainliest answer because I need 5 brainliest answers to get the virtuoso rank and your help can give me my 4th brainliest answer......

Answer 2

Answer:

the answer of this question is - 729