Question

DIVIDE THE FOLLOWING:

3x³-4x²+5x-6÷x+π​

Answer 1

hope this helps u

x+π​

x = -π​

3x³-4x²+5x-6

The zero of x + π is -π.

p(-π) = 3*-π³-4*-π²+5*-π+1

        = -3π³-4π²-5π+1 is the remainder