Math, asked by vidushitiwari0126, 7 months ago

Divide the following algebraic expression using the method of factorisation.​

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Answered by Anonymous
1

 \sf \boxed{Question}

 \sf Divide \\\\\sf</p><p>18x^{12}+21x^9+24x^7\: by\: 6x^2 \\\\\sf</p><p>

 \sf \boxed{Ańšwėř}

 </p><p>=\frac{18x^{12}+21x^9+24x^7} {6x^2}  \\\\\sf</p><p>=\frac{18x^{12}}{6x^2}+\frac{21x^9}{6x^2}+\frac{24x^7}{6x^2} \\\\\sf</p><p>=\frac{18x^2\:x\:x^{10}}{6x^2}+\frac{21x^2\:x\:x^7}{6x^2}+\frac{24x^2\:x\:x^5}{6x^2}  \\\\\sf</p><p>=\frac{ \cancel{18x^2}\:3 \:x\:x^{10}}{  \cancel{6x^2}}+\frac{ \cancel{21x^2}\:7\:x\:x^7}{ \cancel{6x^2}\:2 }+\frac{ \cancel{24x^2}\:4 \:x\:x^5}{ \cancel{6x^2}}  \\\\\sf</p><p>=3x^{10}+\frac{7x^7}{2}+4x^5 \\\\\sf</p><p>

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