Question

Divide the following algebraic expressions using the method of factorisation.(16x^2-56xy+49y^2)÷(4x-7y)

Answer 1

Answer:

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4x−7y

Answer 2

Given :  (16x²-56xy+49y²)÷(4x-7y)      $\frac{16x^2 - 56xy + 49y^2}{4x - 7y}$

To find : Quotient

Step-by-step explanation:

(16x²-56xy+49y²)÷(4x-7y)

$\frac{16x^2 - 56xy + 49y^2}{4x - 7y}$

$= \frac{16x^2 -28xy -28xy + 49y^2}{4x - 7y}$

$= \frac{4x(4x -7y) -7y(4x - 7y)}{4x - 7y}$

$= \frac{(4x -7y)(4x - 7y)}{4x - 7y}$

= 4x - 7y

$\frac{16x^2 - 56xy + 49y^2}{4x - 7y}$   = 4x - 7y

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