Math, asked by Sukhdeep25, 1 month ago

divide the following by long division method :-
a. 3x^4 - 4x^3 - 3x - 1 by x-1 ​

Answers

Answered by trishawath
0

Answer:

ans is :5

step by step explanation

3x^4–4x^3–3x-1)÷(x-1)

3x^4–4x^3–3x-1)÷(x-1)=[3x^3(x-1)-x^2(x-1)-x(x-1)-4(x-1)-5]÷(x-1)

3x^4–4x^3–3x-1)÷(x-1)=[3x^3(x-1)-x^2(x-1)-x(x-1)-4(x-1)-5]÷(x-1)=(3x^3-x^2-x-4) - 5/(x-1).

3x^4–4x^3–3x-1)÷(x-1)=[3x^3(x-1)-x^2(x-1)-x(x-1)-4(x-1)-5]÷(x-1)=(3x^3-x^2-x-4) - 5/(x-1).Thus , Quotient =(3x^3-x^2-x-4). and remainder = -5. Answer.

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