Divide the following by the method of factorisation. 66(y⁴ - 5y³ - 24y²) ÷ 6y(y-8)
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Answer:
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Given : 66y(y⁴-5y³-24y²) ÷6y (y-8)
To Find : divide
Solution:
66y(y⁴-5y³-24y²) ÷6y (y-8)
66 = 6 * 11
Take y² common from the terms inside bracket
= 6 * 11y * y² ( y² - 5y - 24) ÷6y (y-8)
Use middle term split and write -5y as -8y + 3y
= 6 * 11y * y² ( y² -8y + 3y - 24) ÷6y (y-8)
= 6 * 11y * y² ( y(y -8) + 3(y - 8)) ÷6y (y-8)
= 6 * 11y * y² ( (y -8) (y+ 3)) ÷6y (y-8)
= 6y * 11y² (y -8) (y+ 3) ÷6y (y-8)
= 6y (y -8) 11y² (y+ 3) ÷6y (y-8)
Cancel 6y (y-8)
= 11y² (y+ 3)
= 11y³ + 33y²
66y(y⁴-5y³-24y²) ÷6y (y-8) = 11y² (y+ 3) = 11y³ + 33y²
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