Question

divide the following by the method of factorization 121m² - 64n² by 11m - 8n​

Answer 1

Answer:

121 m^2-64n^2

=(11m)^2-(8n)^2

=(11m+8n)(11m-8n)

so,

121m^2-64n^2 by 11m-8n

=(11m+8n)(11m-8n)/(11m-8n)

=(11m+8n)

Answer 2

Answer:

Concept:

$a^{2} -b^{2} =(a-b)(a+b)$

Given:

divide 121m² -64n² by 11m-8n

To Find:

Remainder after diving the equations

Step-by-step explanation:

by concept, $121m^{2}-64n^{2} = (11m-8n) (11m+8n)$

⇒$\frac{(11m-8n)(11m+8n)}{11m-8n}$

⇒11m+8n