Question

divide the following in full method. 2x⁴+2x³-21x²+43x-35 by x²+3x-7​

Answer 1

Answer in Step-by-step explanation:

Let f(x) = 2x⁴  – 2x³  –7x²  + 3x  + 6

Given :

(x+√3/2) & (x-√3/2) are the two factors of given Polynomial f(x).

(x+√3/2) (x-√3/2)

= x²- 3/2 = (2x²-3)/2

= (2x²-3)/2=0

2x²-3 is a factor of given Polynomial f(x)

Divide f(x) =2x⁴  – 2x³  –7x²  + 3x  + 6 by 2x²-3

[DIVISION IS IN THE ATTACHMENT.]

f(x) =2x⁴  – 2x³  –7x²  + 3x  + 6

= (2x²-3)(x²-x-2)

= (2x²-3) (x-2) (x-1)

f(x)=0

= (2x²-3) =0 , (x-2)= 0 , (x-1)=0

x= √3/2, -√3/2, 2 ,-1

Hence , all the zeroes of the given Polynomial are: (√3/2), (-√3/2), -1,2

Answer 2

Answer:

Please refer to the above attachment.

Hope it Helps ^_^