Question

Divide the following polygon into parts(triangle& trapezium) to find out it's area​

Answer 1

Answer:

In the polygon EFGHI, let's draw straight line GJ parallel to diagonal FI and GJ touches the side HI on the point J.

Now the area of Polygon EFGHI = Area of ΔEFI + Area of ΔGHJ + Area of the Trapezium FGJI

In the Polygon MNOPQR, the diagonal NQ is parallel to Parallel sides OP and RM.

∴ Area of Polygon MNOPQR = Area of Trapezium MNQR + Area of Trapezium OPQN.

Step-by-step explanation:

In the polygon EFGHI, let's draw straight line GJ parallel to diagonal FI and GJ touches the side HI on the point J.

Now the area of Polygon EFGHI = Area of ΔEFI + Area of ΔGHJ + Area of the Trapezium FGJI

Area of Triangle = $\frac{1}{2}$ x base x height

Area of Trapezium = $\frac{1}{2}$ x Sum of the parallel sides x height

In the Polygon MNOPQR, the diagonal NQ is parallel to Parallel sides OP and RM.

∴ Area of Polygon MNOPQR = Area of Trapezium MNQR + Area of Trapezium OPQN.