divide the following polynomial 4y^3+8y+8y^2+7 ÷ 2y^2-y+1
Answers
Answered by
2
Step-by-step explanation:
hope this is helpful for you
Attachments:
Answered by
1
Step-by-step explanation:
4y³+8y+8y²+7 ÷ 2y²-y+1
solution:-
= (4y³-2y²+2y) +(10y²-5y+5) +11y+2
= 2y(2y²-y+1) + 5(2y²-y+1) + 11y+2
= (2y²-y+1) (2y+5) +11y+2
divisor× quotient+ remainder
=> quotient= 2y+5
=> remainder= 11y+2
Similar questions