Question

Divide the following question 1+y3 by 1+y

Answer 1

hope this will help u..

Answer 2

$\red{Find \: \frac{(1+y^{3})}{(1+y)} }$

$\frac{(1+y^{3})}{(1+y)} \\= \frac{1^{3} + y^{3}}{(1+y)} \\= \frac{(1+y)( 1^{2} - 1 \times y + y^{2})}{(1+y)}$

$\underline {\blue { By \: Algebraic \:Identity }}$

$\boxed {\pink { a^{3} + b^{3} = (a+b)(a^{2} -ab + b^{2}) }}$

$= 1 - y + y^{2}$

Therefore.,

$\red { \frac{(1+y^{3})}{(1+y)}} \green {= 1 - y + y^{2} }$

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