Question

Divide the given algebraic expression : 15 (y+3)(y2–16) by 5( y2-y +12)

Answer 1

Answer:

Factorising 15 (y + 3) (y2 – 16), we get 5 × 3 × (y + 3) (y – 4) (y + 4) On factorising 5 (y2 – y – 12), we get 5 (y2 – 4y + 3y – 12) = 5 [y (y – 4) + 3 (y – 4)] = 5 (y – 4) (y + 3) Therefore, on dividing the first expression by the second /divide-15-y-3-y-2-16-by-5-y-2-y-12