Question

Divide the line segment of 7 CM in the ratio 3:4

Answer 1

1.Draw a ray AX making acute angle with AB line of 7cm
2.Locate 7poimts such that distance between each point is equal named A1,A2,A3,A4,A5,A6,A7
3.Join BA5
4.Through point A3 draw a line parallel to line BA5 at A3 intersecting AB at pinot C then AC:CB is 3:4

Answer 2

The line segment is internally divided in ratio 3:4 and constructed figure is attached.

Given:

• A line segment of 7 cm.

To find:

• Divide the line segment of 7 cm in the ratio 3:4

Solution:

Steps of construction:

1. Draw a line segment of 7 am, with the help of pencil and scale, let say it is AB.
2. Draw to acute angle ray, one from point A, let say it is AX another from point B,let say it is BY. (Both angles should be same)
3. Make 3 equal mark on AX and 4 equal marks on BY.
4. Join $A_3$ to $B_4$.
5. The line meet AB at a point, let say it is point C.
6. Point C divides AB in 3:4.

Verification:

On measurement we found that

AC= 3 cm

CB= 4 cm

Thus,

AC:CB= 3:4

*It can be done by similarity of triangles.

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