Question

divide the number 1000 into two parts such that their ratio is 1:2​

Answer 1

Answer:

LET THE TWO NUMBERS BE X AND Y

SO X+Y= 100.

Y= 1000-X

NOW FOR PRODUCT TO BE MAXIMUM XY SHOULD BE MAXIMUM OR X(1000-X) SHOULD BE MAXIMUM

SO ITS DIFFERENTIATION SHOULD BE 0

d(x2-1000x)dx=0

2x - 1000= 0

x = 1000/2

x= 500

so numbers are 500 and 500