Divide the number 128 in three parts such that the second part is twice the
first and the third part is 7 less than the second.
Answers
Answered by
2
Step-by-step explanation:
128 = x + y + z
y = 2x
z = y - 7
=> z = 2x - 7
128 = x + 2x + 2x - 7
128 = 5x - 7
5x = 128 + 7
5x = 135z
x = 135/5
x = 27
y = 2x
y = 2 × 27
y = 54
z = y - 7
z = 54 - 7
z = 47
hence proved
Similar questions