Math, asked by skfarmania, 3 months ago

Divide the number 8748 by th smallest number so that the quotient is a perfect cube.Also find the cube root of the quotient​

Answers

Answered by princeuplucky123449
4

Answer:

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Step-by-step explanation:

Given number is 8748

On prime factorising, we get

8748=2×2×3×3×3×3×3×3×3

Grouping of the equal factor in 3’s, it’s seen that 2×2×3 is left without grouping.

8748=2×2×3×(3×3×3)×(3×3×3)

Hence, on dividing the number 8748 by 12, we get 729

And, the cube root of 729 is 3×3=9.

Answered by piyu2009
1

Answer:

=9

Step-by-step explanation:

Given number is 8748

Given number is 8748On prime factorising, we get

Given number is 8748On prime factorising, we get8748=2×2×3×3×3×3×3×3×3

Given number is 8748On prime factorising, we get8748=2×2×3×3×3×3×3×3×3Grouping of the equal factor in 3’s, it’s seen that 2×2×3 is left without grouping.

Given number is 8748On prime factorising, we get8748=2×2×3×3×3×3×3×3×3Grouping of the equal factor in 3’s, it’s seen that 2×2×3 is left without grouping.8748=2×2×3×(3×3×3)×(3×3×3)

Given number is 8748On prime factorising, we get8748=2×2×3×3×3×3×3×3×3Grouping of the equal factor in 3’s, it’s seen that 2×2×3 is left without grouping.8748=2×2×3×(3×3×3)×(3×3×3)Hence, on dividing the number 8748 by 12, we get 729

Given number is 8748On prime factorising, we get8748=2×2×3×3×3×3×3×3×3Grouping of the equal factor in 3’s, it’s seen that 2×2×3 is left without grouping.8748=2×2×3×(3×3×3)×(3×3×3)Hence, on dividing the number 8748 by 12, we get 729And, the cube root of 729 is 3×3=9.

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