Divide the polynomial (18 a2b+6ab2-9ab - 6a3b ) ÷ 3ab?
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Answer:12a²b-9ab² + 6ab
3(4a²b-3ab² + 2ab): = 0
4a²b3ab² + 2ab = 0
ab(4a3b+ 2) = 0
so, factores are
ab (4a - 3b + 2)
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