Question

Divide the polynomial 2x4-2x3-7x2+3x+6 by x2-3​

Answer 1

$\frac{2 {x}^{4} - 2 {x}^{3} - 7 {x}^{2} + 6}{ {x}^{2} - 3} \\ \\ = {x}^{2} - 2x + 4 + \frac{18 - 3x}{ {x}^{2} - 3 }$

I.e.

$( {x}^{2} - 3)( {x}^{2} - 2x + 4) - 3x + 18 = 2 {x}^{4} - 2 {x}^{3} - 7 {x}^{2} + 3x + 6$

hope it helps

Answer 2

this is divide 2x^4-2x+^3-7x^2+3x+6 by x^2-3