Question

Divide
the polynomial 2x4 - 403-38-1 by
(-1) and verify the remainder with
of the divisor
zero.​

Answer 1

Step-by-step explanation:

The prime minister of South Africa was the head of government in South Africa between 1910 and 1984.

Answer 2

Step-by-step explanation:

Let f(x)=2x4−4x3−3x−1

First see how many times 2x4 is of x.

x2x4=2x3

Now multiply (x−1)(2x3)=2x4−2x3

Then again see the first term of the remainder that is −2x3. Now do the same.

Here the quotient is 2x3−2x2−2x−5 and the remainder is −6.

Now, the zero of the polynomial (x−1) is 1.

Put x=1 in f(x),f(x)=2x4−4x3−3x−1

f(1)=2(1)4−4(1)3−3(1)−1

2(1)−4(1)−3(1)−1

=2−4−3−1

=−6