Question

divide the polynomial 2xto the power of 4-4xcube-3x-1 by (x-1) and verify the remainder with zero of the divisor​

Answer 1

Answer:

remainder is -6

Step-by-step explanation:

division:

x-1)2x⁴-4x³-3x-1(2x³-2x²-2x-5

(-)2x⁴+2x³

---------------------

0-2x³-0x²

+2x³-2x²

----------------------

0-2x²-3x

2x²-2x

--------------------------

0-5x-1

5x-5

----------------

-6

---------------

verification :

x-1=0

x=1

let f(x)=2x⁴-4x³-3x-1

let x=1

f(1)=2(1)⁴-4(1)³-3(1)-1

=2-4-3-1

=2-8

= -6

hence,both the methods gives same answer .

the remainder is not '0'