Question

divide the polynomial 3×2-4×3-3×-1 by (×-2)
​

Answer 1

Question:

Divide the polynomial $3x^2-4x^3-3x-1$ by $(x-1)$

Answer:

Quotient :  $4x^2+5x+13x$

Reminder : $14$

Explanation:

You can see that the given Polynomial is not in the proper order i mean see the exponent value and keep it in the order wise.

Here is the correct polynomial

⇒   $-4x^3+3x^2-3x-1$

We can see that the first number if the equation is negative let us convert first number into Positive by multiplying the equation with $-(negative)$.

⇒ $-(-4x^3+3x^2-3x-1)$

⇒ $4x^3-3x^2+3x+1$

Division Process is there in the Attachment

Hence  we will get the quotient as $4x^2+5x+13x$ and the remainder is $14$.