Question

Divide the polynomial 3x²-4x³-3x-1 by x-1​

Answer 1

Answer:

Given that,

f (x) = 4x^3 - 2x^2 + 4x -7

If we divide f(x) by (x -3), the remainder of this polynomial will be f(3)

f(3) = 4(3)^3 - 2(3^2) + 4(3) -7

= 4. 27 - 2. 9 + 12 - 7

= 108 - 18 + 12 - 7

= 95

So, the the remainder is 95.

Here,

Dividend = 4x^3 - 2x^2 + 4x -7

Divisor = 3

Remainder = 95

We know,

Dividend = Divisor × Quotient + Remainder

=> 4x^3 - 2x^2 + 4x -7 = 3 × Quotient +95

=> 4x^3 - 2x^2 + 4x -7 - 95 = 3 Quotient

=> 3 Quotient = 4x^3 - 2x^2 + 4x -7 - 95

=> 3Quotient = 4x^3 - 2x^2 + 4x -102

=> Quotient = (4x^3 - 2x^2 + 4x -102)/3

If you don’t apply this formula, it will take much time and will be harder for you.

Good luck and thank you for requesting me.