Divide the polynomial 6x^3-19^2-3x+11 by 6x^2-x-2 and verify the result by division algorithm
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firstly factorise divisor as the dividend is not symmetrical
6x^2 - x - 2
6x^2 +3x - 4x - 2
3x(2x+1) -2(2x +1)
(3x+2)(2x+1)
find value of x
2x+1=0
2x=-1
x= -1/2
then do the same with 2nd factor and multiply them and find third factor from division method. you will get another factor and find values of x from all the factors and fill in the polynomials line vise and you will get the result
6x^2 - x - 2
6x^2 +3x - 4x - 2
3x(2x+1) -2(2x +1)
(3x+2)(2x+1)
find value of x
2x+1=0
2x=-1
x= -1/2
then do the same with 2nd factor and multiply them and find third factor from division method. you will get another factor and find values of x from all the factors and fill in the polynomials line vise and you will get the result
brainly121brainiton:
divisor tak pata chal gaya
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0
X is -1/2.........................
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