Question

divide the polynomial 6x^4+5x^3+3x-5 by 3x^2-2xand write in the form of p(x)=g(x).q(x)+r(x)​

Answer 1

Step-by-step explanation:

p(6x^4+5x^3+3x-5)=g(3x^2-2).q(2x^2+3x)+(9x-5)

Answer 2

quotient = 2x²+3x+2

remainder = 7x-5

Step-by-step explanation:

given polynomial $6x^4+5x^3+3x-5$ dividing by $3x^2-2x$

using long division method , the division is shown in the below attachment

the quotient = 2x²+3x+2

remainder = 7x-5

then p(x) = g(x) .q(x) +r(x)

$6x^4+5x^3+3x-5$ = $3x^2-2x$ .(2x²+3x+2) +(7x-5)

$6x^4+5x^3+3x-5= 6x^4+9x^3+6x^2-4x^3-6x^2-4x+7x-5$

$6x^4+5x^3+3x-5= 6x^4+5x^3+3x-5$

LHS = RHS

hence  proved

#Learn more:

On dividing the polynomial x³ -5x² + 6x -4 by a polynomial g(x), quotient and remainder are (x –3) and (– 3x + 5) respectively. Find g(x).

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